travis newberry wrote:well idk hondas so 140 was a guess...
origin of 5252 anyone?
short answer: 5252 ≈ (60*550) / 2π
long answer: http://faraday.physics.utoront....html
travis newberry wrote:how does that work... a torque curve isnt a linear equation so how you can use an equation that doesnt take into anything but a simple rise/run formula. it is basically saying that every car that makes 200hp at 5252 rpm will make 457 hp at 12000 rpm. that can not be true. for example if you use a lower rpm, like 2500, to use in the equation you would get 95 hp. idk if that is a reasonalble number, but if an engine was turbo it would def not have the same power at 2500rpm as a SC engine would, or a NA engine. i am not arguing with you, but i never believe something until i understand it.
educate me
A torque curve is not completely linear, so you cannot apply the conversion equation as if it were a linear equation (which is what your logic is suggesting).
By saying: if 200 HP @ 5252 RPM, then 457 HP @ 12000 RPM, you're suggesting that the torque remains 200 for all RPMs and never changes, which would be the linear function: HP = RPM*(200/5252). So plugging in 5252 RPM gives you 200 HP, 12000 RPM gives 457 HP, 2500 RPM gives 95 HP; as you've just done.
Remember, there are 3 variables that have to change, not just the two you were looking at (HP and RPM). You have to take into account that torque values may be different at different RPMs.
Use Mr. Knight's dyno sheet as an example. At 2000 RPMs the TQ is about 155. Using the conversion equation: HP = (RPM*TQ)/5252HP = (2000 RPMs * 155 TQ)/5252HP = 59.02
At 4000 RPMs the TQ is about 215.HP = (4000 RPMs * 215 TQ)/5252HP = 163.75
What you were doing was keeping the TQ value constant for all the RPM values you were using.
Modified by Rich_S14 at 9:04 AM 10/23/2006