HAVING THE FACTS ON YOUR SIDE IRRITATES THE IGNORANT. FROM THE DYNOJET'S TECHNICAL INFORMATION, THEY QUOTE EXACTLY WHAT I HAVE ALREADY SAID. IT IS IMPOSSIBLE FOR ANY DYNO RUN WHEN PROPERLY SETUP AND CALCULATED TO NOT HAVE THE HP/TQ CROSS AT 5250 (5252 TO BE EXACT). AINT THE TRUTH A BIATCH SOMETIMES?Chezedik wrote:Thank you, I told a friend about the 5252 thing months ago, and he called me a liar. Maybe a little petty, but maybe I will have to give him a call.
IF WE HAVE A 1FT BAR WITH A 1LB WEIGHT AT THE END, AND WE MOVE THAT 1LB WEIGHT FOR ONE FULL REVOLUTION AGAINST A ONE POUND RESISTANCE, WE HAVE MOVED IT A TOTAL OF 6.2832 FEET (PI=3.1416 X 2FT CIRCLE) WE HAVE DONE 6.2832 FT/LB OF WORK. THE WATT EQUATION OF 32,580 /6.2832 = 5252, WHICH IS THE CONSTANT. JUST REMEMBER THAT THERE IS NO ACTUAL MEASUREMENT OF THE HP ON ANY DYNO--ONLY TQ. THEN THE FORMULA TRANSLATES TQ INTO HP. THIS GIVES A CALCULATED AND ACCURATE COMPARISON FROM ENGINE TO ENGINE. ONE MORE ITEM TO DO JUST FOR FUN. IF YOU MAKE 200FT.LB @ 5252 RPM, HOW MUCH HP WOULD YOU MAKE AT 12K RPM LIKE AN INDY MOTOR?travis newberry wrote:well idk hondas so 140 was a guess...
origin of 5252 anyone?
OK--LETS LOOK AT THE FORMULA--TQ X RPM DIVIDED BY 5252 = HP. TQ IS 200. RPM IS 12,000. SO 200 X 12,000 DIVIDED BY 5252 = 457HP @ 12K RPM. BUT THE LINES WOULD STILL CROSS AT 5252 RPM (TQ & HP WOULD BOTH BE 200). I AM 50 YRS OLD, AND I READ FOR HOURS EVERY DAY. GET AS GOOD AN EDUCATION AS YOU CAN.travis newberry wrote:yea, i was crunching some numbers this morning and nothing worked... but it makes sense now
i dont understand how to calculate that little problem at the end, or even if it was to be figured out. how can you calculate what hp an engine will be at given a certain rpm? curves are different with each motor so there isnt a way to just figure it out with the numbers given. all i got was hp= 2.284(tq) and since the curve isnt linear you cant solve for 200hp at 5252 rpm and plug in the slope. idk, its been about 2 years since high school calc and 3-4 years since algrbra/graph stuff so maybe im a little rusty and missing something, but i am planning on going back to college for mechanical/automotive engineering next fall so i need to get back into learning/knowing.
OK--LETS DO IT A DIFFERENT WAY. LETS USE THE FORMULA TO DETERMINE ANY HP OR TQ AT A SPECIFIC STATED AND KNOWN RPM. LOOKING AT OUR DYNO THE PEAK TQ OCCURED AT ABOUT 3800 RPM AND SHOWS 217 TQ.217 X 3800 / 5252 = 157HP, WHICH COINCIDES NICELY WITH THE GRAPH.UPON CLOSE EXAMINATION OF THE 271 DYNO GRAPH, I REALIZED THE COLUMN ON THE RIGHT IS KPA (ONE OF THE THE EUROPEAN RATINGS FOR PRESSURE), NOT FT/LB. KPA IS THE READING OF HOW MUCH BOOST THIS GUY WAS RUNNING, NOT TQ. 101 KPA = 1 ATMOSPHERIC PRESSURE. THE PEAK KPA WAS 170, SO 170/101 = 1.69 PRESSURE RATIO. USING OUR CONVERSION FACTOR OF PR = PSI + 14.7 /14.7, WE SEE 1.69 X 14.7 - 14.7 = 10.1 PSI BOOST. USING THESE NUMBERS STARTS TO ADD UP. THIS IS A EUROPEAN DYNO THAT MEASURES IN CONVERTED FLYWHEEL HP. SO, ASSUMING 150 HP, PLUS 10% FROM THE LARGER ITB'S, WE COULD GET:150 + 10%, X 1.69 PR = 278 FLYWHEEL HP. NOW IT ALL STARTS TO MAKE SENSE. HE WAS MAKING 271 FLYWHEEL (NOT WHEEL HP) @ 10 PSI BOOST, NOT 7 PSI. I WENT TO THE DYNO MANUFACTURERS SITE (MADE IN AUSTRALIA), AND THEY USE THE METRIC SYSTEM. SO IT ALL MAKES SENSE NOW. BOOST WAS IN FULL BY 3900 RPM.Malac0da13 wrote:im seeing the same logic that you r seeing...i mean i understand the converting torque...it seems like its an arc and should have like sine or cosine or tangent or sumptin like that...but what do i know i slept thru calc and failed it cuz i didnt understand derivitives
IT IS QUITE COMMON FOR MODERN TWINCAM 4-VALVE ENGINES TO REACH 100% OR HIGHER VE W/O BOOST, ESPECIALLY AT THE TQ PEAK. REGARDLESS OF THE RPM, THESE FORMULAS ARE ACCURATE DESPITE THE VE, AE, OR ANY VARIATION AS THEY ARE BASED ON ONE SET OF NUMBERS--THE DYNO'S TQ NUMBERS. THE DYNO DOES NOT TAKE INTO ACCOUNT VE OR ANYTHING OTHER THAN THE TQ REQUIRED TO SPIN THE DRUM AND THE ENGINE'S TACH SIGNAL TO DETERMINE RPM. ONCE WHEEL TQ IS KNOWN AT ANY GIVEN RPM, HP IS AN AUTOMATIC CALCULATION. EVEN SAE, DIN, AND OTHER RATINGS USE THE SAME ACCEPTED FORMULA. WHEN A FACTORY MOUNTS AN ENGINE TO AN ENGINE DYNO, THE DYNO ONLY MEASURES TQ. ALL OTHER RATINGS COME FROM THE ACCEPTED CONVERSION FORMULAS. VE, AE, THERMODYNAMIC EFFICIENCIES, ETC HAVE ABSOLUTELY NO BEARING ON THE OUTCOME. ONLY MATH DOES.Chezedik wrote:He is absolutely right assuming a constant VE of 100%. But in the real world VE does change at a given RPM, or more importantly air velocity. So, while this can be used to make rough calculations, this can never be used as a steadfast rule for determining power. But it is good information, and all things being equal, is accurate.
if there is a high enouigh demand for the ka-e, we will offer an eaton kit for it also. it would perform at about the same level as the dohc kit. if three or more people place a deposit, we will produce the kits.benemorius wrote:I really hate to do this. I've tried really hard to keep up with all the posts in this thread but it's a big *** thread. I'd just like to know whether an eaton kit is being or will be offered for the ka24e. I know I saw that a centrifugal kit is, but I just wasn't sure about an eaton.
That's the post I am talking about. I think he is legit to because the next post is SCMASTER and he doesn't say anything about this guy being a fraud.turbo300 wrote:the new website for the supercharger systems will be up soon. it will have pricing, pics, descriptions, dyno videos and a forum moderated by mr. knight and myself. we will be releasing eaton based kits for twin cam ka's and intercooled centrifugal supercharger kits for both e and de's. we are also currently in the process of creating ka block to vg30dett trans adapters, z32 eaton kits, altima kits (eaton and centr.), new intake and turbo manifolds and twincharged ka packages.
the new site will be done soon, in the meanwhile deposits on eaton-based kits will be taken at the boosthead site.
http://www.boosthead.com
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