Usually no because its in the garage all nightYes for a minute or so if its been outside for a few hours and the temperature is below 20F2 minutes if the temp is below zerorn79870 wrote:When you first start your car in the morning, do you warm it up, or do you just drive away?
When I do a cold start mine idles at about 2100rpm, and it takes about 30 seconds to drop to 1100. Having the 5AT, I don't like to drop it into reverse with the engine spinning at 2100rpm, so I wait.
Do you wait for the temperature gauge to register, or the rpm to drop, or do you drive away after starting?
Actually it does recharge. But it is unpractical to think that charging a battery is a good reason to let a car idle in the morning. The draw on the battery over a day is minimal. And frankly, the drive to work would be more than adequate to charge the battery.Focusedintntions wrote:On a side note...you car battery does not recharge while your car is idling....you need to get the rpms up on the the alternator to charge the battery up...usually above 1500-2k rpms
Ever tried to jump a car and have to rev the motor to get the other car to jump?? that's why...not enough juice being put out
That's not a good example. I tried jumping a caprice with my car and it would because it needed a huge CCA and higher voltage.Focusedintntions wrote:30 seconds or so...just long enough for me to get on my seat belt, put on my traffic station, put my phone in the cup holder, and take a quick sip of my coffee....
On a side note...you car battery does not recharge while your car is idling....you need to get the rpms up on the the alternator to charge the battery up...usually above 1500-2k rpms
Ever tried to jump a car and have to rev the motor to get the other car to jump?? that's why...not enough juice being put out
Sorry, but no. The resistance is not the factor that keeps the car from starting. The jumpee car's battery and starter are on a parallel circuit. As such, the total resistance that exists for the entire circuit will always be less than the component that has the least resistance.Jacko3 wrote:C-Kwik is correct. The resistance he speaks off, is called electrical resistance. Voltage = Current (I) x Resistance (R). Most elctrical system, so long as they have some wire connection, will present some resistance.
Geez, you'd think a dissertation was being requested for a simple question...rn79870 wrote:When you first start your car in the morning, do you warm it up, or do you just drive away?
When I do a cold start mine idles at about 2100rpm, and it takes about 30 seconds to drop to 1100. Having the 5AT, I don't like to drop it into reverse with the engine spinning at 2100rpm, so I wait.
Do you wait for the temperature gauge to register, or the rpm to drop, or do you drive away after starting?
C-KwikC-Kwik wrote:
Actually it does recharge. But it is unpractical to think that charging a battery is a good reason to let a car idle in the morning. The draw on the battery over a day is minimal. And frankly, the drive to work would be more than adequate to charge the battery.
As for the reason you need to rev up a motor that is trying to jump start another vehicle is because you typically have to overcome not only the starting amps required by the jumpee, but also the elecgtrical load the jumpee's battery is placing by trying to charge itself off the jumper's electrical system. While not recommended in newer cars, disconnecting the battery from the jumpee and attaching the jumper cables to the battery cables directly will allow the car to start without revving it.
Fascinating explanations; however, voltage (E) never = current (I) alone, resistance (R) is integral to the equation. And I believe that the more accurate way of representing the equation, for our purposes would be I=E/R.Jacko3 wrote:C-Kwik:
If you are right about the parallel arrangement of the circuits, then i would agree completely with your equation. Thus making resistance a less of an issue. The equation you presented is the correct equation for resistance in parallel connections, as opposed to resistance in series which would look like
Rtotal = R1 + R2 + R3 + .... + Rn.
However, according to Ohm's law, Voltage (V) = Current (I) x Resistance (R). Thus, the little resistance, as you have aptly suggested in your equation Rtotal = 1/R1 + 1/R2 + 1/R3 + .... + 1/Rn,
Would infact contribute very little in the Potential differece or Voltage (V) when Current (I) is multiplied by Resistance (R). Thus, the new equation, would be
Voltage (V) = Current (I) (because R, is no more needed, as it contributes very little to the charge or discharge).
So, what really matters as you have rightly said, "The factor here is the current draw" is what we call the electromotive force, which does determine the level of charging or discharge of current.
In essence, you are presenting very important parts and aspects of the overall equation I had earlier presented.
V and E are interchangeable actually. E was used decades ago and has been around much longer. it was recently changed to V.... we're saying much the same thing tho. Thanks for clarification, I wasn't reading the argument carefully.Jacko3 wrote:W661335PF:
C-Kwik accurately noted a point. In physics and the sciences, when a factor becomes negligible or infinitessimal, it is removed. In essence, I am saying that Rtotal = 0 or negligible as C-kwik had noted. To that extent, the equation automatically reduces to
Voltage (V) = Current (I)
This does not mean that the equation V = I x R does not hold. It only means that by the assumptions suggested by C-Kwik given the conditions we have both stated, the final equation, for our specific case will ultimately become;
Voltage (V) = Current (I)
In addition, Voltage is typically denoted by V and not E.
And i am not sure what point your are trying to make by stating that
I = E/R.
If you replace the letter E with its proper nomenclature of V, what you have is
I = V/R
If you remove the denominators on all sides, what you then have is
I (Current) x R (resistance) = V (voltage), which is exactly what i had earlier stated in all my comments.
Let me help you a little bit in the mathematics of this matter, by stating some obvious mathematical derivations of this issue:
1. V = I x R
2. V/I = R, as long as I is never equal to zero or infinity
3. V/R = I, as long as R is never equal to zero or infinity
Replace V with your E and you can see that you are saying the same things as I, but using atypical nomenclature.
Voltage is generally represented by V while elctrical energy is typically depicted with E or W. Power is depcted with P. The sciences have specific symbols that most around the world, tend to adhere to. Even more restrictive in nomenclature, if we take a look at it, is the use of the S.I units.
However, it is okay to express liberty in the use of nomenclatures.