Post by
KATwo40 »
https://forums.nicoclub.com/katwo40-u25350.html
Fri Mar 24, 2006 10:28 am
The conversion between lb/min and CFM is relative to the atmospheric conditions in which the measurements are taken or calculated.
For example, say you have a figure of 250CFM and want to convert to lb/min at approx. 1,000ft above sea level. You'd multiply 250x.0997 to get the lbs/min.
However, if you were in Aspen, CO, which is about 8,000ft above sea level, you'd multiply 250x.0972 because now the air density has drastically changed.
Here's a for calculating CFM requirements of any engine at any given RPM. This is from Corky Bell's "Maximum Boost." While I don't quite agree with Corky's theories and suggestions 100%, I find this formula very useful, and he is a very knowledgeable person.
Airflow = Cubic Inch Displacement (CID)x RPM x 0.5 (two revolutions per cycle) x VE / 1728 (to convert to CFM)
So here we go:
Airflow = CID x RPM x 0.5 x VE / 1728 = CFM
= 146 x 6800 x 0.5 x .85 / 1728 = 244.18
Then you have to convert to lb/min via your relative air density.
In my case, I'm about 1100 ft. above sea level.
Airflow = CFM x Relative Air Density = lb/min
= 244.18 x 0.0997 = 24.34lb/min.
Now, if you incorporate boost, you multiply by the pressure ratio.
Say you have a pressure ratio of 1.72 (about 9psi).
lb/min x 1.72 = lb/min under boost.
24.34 x 1.72 = 41.86 lb/min @ 6800rpm
Hope this is useful to you.