rn79870 wrote:Unsprung weight has more of an affect on on acceleration than an equal amount of sprung weight. The car has to overcome the inertia of the wheel x 4 to accelerate from a stop. Overcoming that inertia takes power that would otherwise be busy accelerating the car down the street. In any event, I would guess it was not enough difference to really be noticeable but apparently it is.Suggestion. Take one off the car and weigh it. Weigh the stock wheel. Report the results.
The good news is that you've got 19 inch wheels.
I think you have your terms mixed up. The concept is correct, but the terminology you are actually describing is rotational mass/inertia. Unsprung weight with respect to automobiles tend to repate to the wiehgt of the wheels and suspension pieces and their effects on the suspension movement.
As for weighing the wheels, it only tells part of the story. While it certainly has some relation, it is more important to know where the weight is on a wheel. Or more scientifically, you need to know the moment of inertia. If more of the wheel's mass is located further out from the center of the wheel, the more force will be required to move it. Think of it like a lever. using the same weight at various points on a lever will apply various amounts of force on the other end of the lever. The closer the weight is to the fulcrum, the less force it will apply. In a wheel of a specific design, a larger wheel will put more mass out further from the center of the wheel. Assuming the thickness of it's parts are the same, a larger wheel will have proportionately longer spokes which adds a little bit more mass. But the biggest mass increase will be in the rim as it is not only further out, but has to increase the amount of material to span the greater circumference of the wheel (which is 3.14 times the increase in diameter). Not to mention that a wider wheel will need more additional material than a narrower one. This is before we even add in the effects a tire might have in this.
Tires are the same way, but as you get into lower profiles, it becomes a bit simpler as there is less sidewall height to account for. But the same principle applies. But one consideration for a tire with respect to the moment of inertia is that with a larger diameter wheel, the inner diamter is further out than a tire with a smaller diameter. So if the tire is just as heavy or heavier than it's smaller diameter counter part, it is likely there is much more mass further out on the wheel/tire assembly than the smaller wheel/tire combo. This is true even if the outer diameter is the same. Just as a reference, the Bridgestone RE050A in the 245/40/19 are a pound or two heavier than a 245/45/18 of the same tire. On the other hand the Michelin PS2 has a 1 pound difference in the other direction. So it's not necessarily predictable by tire size. Of useful note about the PS2's is that they are 5 pounds lighter than the the RE050A's in the 19 inch size (245's). Just something to think about when tire shopping...
The stock 19's on the G35 are forged so they may be just as light as the stock 18s or lighter, but the tires may be an even bigger factor in this case.