I am thinking of building a custom ram air intake that would be able to produce significant air pressure at speedsover 30mph. The following calculations could be wrong but if they are right, according to them, the vq35de would have a theoretical CFM of 6.5 cubic feet/s at 6000rpm, while a 2ft^2 area ram air has the potential to get 87 cubic feet of air at say correspondingly 30mph, with 80 cubic feet/s for the FI affect, atleast a few psi right?? if 87
if this article/page on converting air speed to pressure is correct
http://www.ehow.com/how_5814125_convert ... ssure.html
say an air box is made with a direct ram air opening of 2 square feet
at 30 mph, according to the article
(30^2) x (0.0027) x 2.0 = 4.86psi
a surface of frontal surface area of 2sq.ft should face 4.86 psi of air pressure when travelling at 30mph.
If we know how much air the engine is taking is, im guessing we could estimate the left over air that would exert its pressure in the ram air box.
so at 30mph (48km/hr); 13.3m/s --> 43.6ft/s, the 2ft^2 area pushes through (87.2ft^3) of air every second.
I do realize that the pressure difference form the pressure on the car's surface makes the air flow around the car
so not all of the 4.86 psi of air pressure will be exterted on the 2ft^2 area but due to the lack of a wind tunnel, ill shall make assumptions
for 4 stroke engines
the CFM(air flow rate) = [((displacement in inches) x 6200rpm x VolumetricEfficiency)/3456]
This guy is japan was comparing the improvements in the vq35de and the vq35hr platform. The graph shows a comparison of the VE of the de engine around 1.05, so VE = 1.05
http://books.google.ca/books?id=oHmb86m ... cy&f=false
CFM=218 x 6200 x 1.05 / 3456 = 410.64 cubic ft/ minute = 6.84 cubic ft/second
so the ram opening has the potential of taking in 87 cubic feet of air,
at 6000rpm, over 30mph with some wind, If I am assuming right, this will change the delta of the stock pressure difference between on front of the intake and the end of the intake runners.
so (80cubicFt)
Im thinking it cant be that simple or I am probably assuming something wrong cuz an extra 87cubic feet of air is alot, even if I take 0.5ft^2 of ram intake area, I may get around 21cubic feet of air, 21-7=14 cubic feet of air/s for the FI effect
Does it sound like it will work??
any one know any thermodynamic formulas to relate pressure difference to the difference in volume of air going into and out of the system??


