AZhitman wrote:3" exhaust on a n/a KA is ignorant. Sure your peak hp increases, but look at the torque curve down low. That same car that supposedly pulled 13+ hp out of a 3' catback would run .2-.4 SLOWER in the 1/4. So dyno numbers become meaningless.
I'm gonna have to disagree with this.
Horsepower is a measure of work. Work is what actually moves the car, since it by definition is the amount of mass moved x amount of distance per unit time. Granted in order to achieve work you must have a force, torque. The more torque you have the more work at that give amount of time, true. However, when you include engine rpm into the mix then the amount of work moves up as the RPM's increase even though the torque value can remains the same. What you get is faster acceleration even though amount of torque is exactly the same. The same goes for when you gain a minute amount of torque at a high rpm, the amount of work gained is higher than if you had gained the same amount of torque at a much lower rpm. It is because of that principle that torque plays only a role in actual vehicular acceleration, it is not the end all to movement.
HP = Tq *RPM / 5252
Lets say at 2000 RPM the 3" Exhaust 240 makes 5 lb. ft. less torque @ 140 lb. ft.
X = 140 x 2000 / 5252X = 53.3 HP
By comparison - the stock 240
X = 145 x 2000 / 5252X = 55.2 HP
Delta X = 1.9 HP
Now lets say at 6000 RPMs the 3" Exhaust car makes 5 lb. ft more torque @ 130 lb. ft.
X = 130 x 6000 / 5252X = 148.5 HP
In comparison the stock 240
X = 125 x 6000 / 5252X = 142.8 HP
Delta X = 5.7 HP
Now some calculations:
1 HP = 1000 lbs. X 33 ft.
or
1 HP = 3000 lbs X 11 ft. (3000 lbs. = weight of 240 w/ driver)
now
5.7 HP = 3000 lbs. x 62.7 ft.
Meaning 5.7 HP can move a 3000 lbs. object 62.7 ft. in one minute.
1.9 HP = 3000 lbs. x 20.9 ft.
Meaning 1.9 HP can move a 3000 lbs. object 20.9 ft. in one minute.
Translated into movement differences.
53.3 hp = 3000 lbs. x 586.3 ft. 55.2 hp = 3000 lbs. x 607.2 ft.
Delta ft. = 20.9 ... notice the above value the 1.9 HP formula
148.5 hp = 3000 x 1633.5 ft.142.8 hp = 3000 x 1570.8 ft.
Delta ft. = 62.7 ... notice the above value in the 5.7 HP formula
While at the lower RPM the stock 240 may gain a small advantage the other 240 will overtake that advantage and proceed to put 2/3rds. more space between the two.
There you have it... the higher the RPM value the more crucial the torque value becomes. So the focus on making a vehicle accelerate should be in the production of high end torque which is easier translated into the production of horsepower.
However, a common misconception is area under the curve means a faster car. Untrue by the math above. You want to move as much area as possible into the USEABLE RPM range for maximum acceleration. When you upshift a 240 you drop down to around 4000 rpms or so, so what good is producing power below 4000 rpms other than daily drivability? It doesn't make you faster to produce 50 ft. lbs. more torque at 2000 rpms when you are never at 2000 rpms in the course of a 1/4 mile.