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Q45tech »
https://forums.nicoclub.com/q45tech-u112.html
Mon Aug 11, 2003 8:46 am
The question of different sizes should consider that larger tires [higher load index ratings] have less slip angles for the same loaded weigh than lesser index tires.
This factor not necessarily the tread width is why designer use this concept.......many times it is a blend of the two.Don't ASSUME that wider tires always have a higher load index!
Almost always a RWD [or a FWD] has more friction potential on the lighest portion of the car. Until you start accelerating, then the total friction is proportioned between acceleration and handling [accelerating out of a curve] in a RWD.
The fronts are nearly always overloaded [engine weight] and the rear are underloaded by static weigh alone. Because manufacturers are allowed to spec only a 12% reserve.
Each tire has a different slope on the graph of friction vs loaded weigh.............the graph is linear [[1 LB of wight = 1 lb of friction x for tread compoud]] up to 75-80% of the maximum weight and inflation pressure. THEN the graph noses over and 1 lb of extra weight may only create 0.9 then 0.8 then 0.7 lbs of extra friction.Ideally one would want tires that have a FULL 25% or more reserve for the total static and handling weight. Unfortunately ~~~1650 pounds is the limit for street tires in V/Y/Z rating.limits.Racing slicks can have friction potential greater than 1.0:1 and street tires are around 0.85>0.9:1 and all season tires can be 0.75:1 and snow tires can be 0.60:1.
The reason all cars don't handle at 1.0 G is that the tires are overloaded by the handling forces. Larger stronger tires on the heaviest end will improve this.
Backwards from what most believe [in an understeering car] the strongest tires should be on the heaviest end.
In a powerful RWD car you must provide ample friction for both acceleration and simultaneous handling [or you get fish tailing and oversteer in acceleration].