jeb1517 wrote:How can big turbos supply more air but be at the same pressure if the volume of the intake manifold hasn't changed? 10 psi going through the manifold should be the same amount of air.
Obviously I'm missing something since bigger turbos do offer more power so can someone please explain it to me?
EDIT: Here's exactly what's confusing me:
Ideal gas law: PV=mRT
In order to make more power, I would have to increase the amount of gas (air) going into the engine (increase m). R is constant and we are holding P constant (10 PSI let's say). The intake manifold is unchanged so V is also constant???? But If I increase m, either V has to increase, or T has to decrease. I would think T remains relatively constant (so maybe this is what I'm missing?)
Modified by jeb1517 at 7:55 PM 10/2/2009
It has nothing to do with where you're referencing pressure from. It has everything to do with how much the air heats up as it's compressed. Larger turbos are more efficient, meaning they heat the air up less than a smaller turbo does. (you can look at a turbo compressor map for this info) It has also been mentioned that a bigger turbine will reduce backpressure and increase volumetric efficiency.
Take a look at this thread:
zerothread?id=381746
You've got the right idea with the ideal gas law. just remember that we're doing with air FLOW not a constant mass that gets compressed and uncompressed.(that's essentially all you can do with PV=mRT) What you want is to use P*volumetric flow= mass flow * R * Temp. .volumetric flow is equal to engine displacement*rpm*volumetric efficiency/2 (the 2 is because there is a power stroke every 2 revs). So you end up with this:
P*engine displacement*rpm*volumetric efficiency/2= mass flow * R * Temp
You want to maximize mass flow, so you maximize pressure(boost), minimize air temperature(intake temps) and you want to maximize volumetric efficiency. However, these three variables are interrelated - you just need to strike the right balance to make the most power.
hope that helps.